Ill give you that I abstracted a bit, but given the mass, which is very small since only section very close together can be counted for the gravitational force at any point, we are looking at the distance (1 AU) of the ringworld, and given that its circular you get a very small force, basically negligible force.
If we assume a Star of the Suns mass (not unreasonable since we are using a AU distance ) then a simplified representation of the force is:
Fg1 = GmM/r^2
Where M = 1 solar mass r = 1 AU G = the gravitational constant
Fg1 = (6.67408 × 10-11 m3 kg-1 s-2)(m kg)(1.989 × 10^30 kg)/(149 597 870 700 m)^2
Fg1 = (0.00593 * m) N
If we assume only the opposite side of the ringworld has any counter balance effect, then the maximum possible additional distance is 1 391 400 000 m. This gives:
Fg2 = (6.67408 × 10-11 m3 kg-1 s-2)(m kg)(1.989 × 10^30 kg)/(149 597 870 700 m + 1 391 400 000 m)^2
Fg2 = (0.00582 * m ) N
Thus we get 0.00011 * m N of net force at the furthest possible distance from the star.
If we assume that a section, m, is 0.00017453 radians (0.01 degree) then we get the arc length of a section to be 26 109 875.4 m, 12 000 000 m tall and say 500 m deep, for a volume of 1.56659*10^17 m^3. If we then assume this has a density equivalent to 1/10 of earth (since we are smart and not using solid rock to build this) then we get 8.63819*10^20 kg of section. This then gives us a net force of 9.50201 *10^16 N (assuming I haven't made a mistake). While this seems very large, when compared to the earths gravitational pull, 3.54162 * 10^22 N, to the sun we see its rather small being ~1 000 000 times smaller.
Now considering that we are ignoring the other 359.98 degrees of this ringworld it is safe the say the net force on a point on the suns surface is even less, likely approaching zero. Even assuming it does not get further reduced (which it does), considering that the rotation of the Earth and other planets does not cause destructive events on the sun, I would hypothesis that a Synthetic sun with only a ringworld orbiting it would experience no more solar weirdness than Earth currently does.
Note: If we use theDungeons 14 m depth we get a force ~10,000,000x smaller.
Note2: The section length I used is probably too large, but I abstracted it by assuming only points within 0.01 degree were distances, R, from point, p. I expect +/- 10% error as a result.
Disclaimer the above math is more probably right, but owning to abstractions we should keep in mind it is not a perfect model of what happens.